(2x^2+3x-2)(5-6x-4x^2)=-5(2x^2+3x+2)

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Solution for (2x^2+3x-2)(5-6x-4x^2)=-5(2x^2+3x+2) equation: 



(2x^2+3x-2)(5-6x-4x^2)=-5(2x^2+3x+2)

We move all terms to the left:

(2x^2+3x-2)(5-6x-4x^2)-(-5(2x^2+3x+2))=0



We calculate terms in parentheses: -(-5(2x^2+3x+2)), so:

-5(2x^2+3x+2)

We multiply parentheses

-10x^2-15x-10

Back to the equation:

-(-10x^2-15x-10)



We get rid of parentheses

(2x^2+3x-2)(5-6x-4x^2)+10x^2+15x+10=0

We add all the numbers together, and all the variables

10x^2+(2x^2+3x-2)(5-6x-4x^2)+15x+10=0

We move all terms containing x to the left, all other terms to the right

10x^2+(2x^2+3x-2)(5-6x-4x^2)+15x=-10

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